That's Heron's formula that I mentioned.
It's a funny question, as the only ways I can find to get the perpendicular height require you to first get the area (either from the standard half times base times height formula) or using the uglier heron's formula. You'll get the same answer either way.
If it's any comfort, I did come across a reference to this exact same problem on a mathematics forum... and they have the exact same solution as I do.
BW


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What I'm struggling to believe is that I actually used to be able to do this stuff...........now I wouldn't have a clue



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